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15x^2+100x-16=0
a = 15; b = 100; c = -16;
Δ = b2-4ac
Δ = 1002-4·15·(-16)
Δ = 10960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10960}=\sqrt{16*685}=\sqrt{16}*\sqrt{685}=4\sqrt{685}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{685}}{2*15}=\frac{-100-4\sqrt{685}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{685}}{2*15}=\frac{-100+4\sqrt{685}}{30} $
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